MIT 18.650 — Lecture 4

The Normal Distribution

Definition. The normal distribution X∼N(μ,σ2)X \sim \mathcal{N}(\mu, \sigma^2) has PDF given by f(x)=1σ2πexp⁡(−(x−μ)22σ2)f(x) = \dfrac{1}{\sigma \sqrt{2\pi}} \exp\left(-\frac{(x - \mu)^2}{2 \sigma^2}\right).

Definition. For any X∼N(μ,σ2)X \sim \mathcal{N}(\mu, \sigma^2), we say Z=X−μσZ = \frac{X - \mu}{\sigma} is the z-score of XX.

Note that if X∼N(μ,σ2)X \sim \mathcal{N}(\mu, \sigma^2), then aX+b∼N(aμ+b,a2σ2)aX + b \sim \mathcal{N}(a \mu + b, a^2 \sigma^2), expectedly. Therefore,

Theorem. (Z-Score) The random variable Z∼N(0,1)Z \sim \mathcal{N}(0, 1) has PDF given by f(x)=12πe−x2/2f(x) = \frac{1}{\sqrt{2\pi}}e^{-x^2/2} and CDF Φ(x):=∫−∞xf(t) dt\Phi(x) := \int_{-\infty}^x f(t) \, \mathrm{d}t.

Example. Given that X∼N(4,4)X \sim \mathcal{N}(4, 4), compute Pr⁡(0≤X≤10)\Pr(0 \leq X \leq 10).

Solution: Considering the z-score Z=X−42Z = \frac{X - 4}{2}, this is just Pr⁡(−2≤Z≤3)\Pr(-2 \leq Z \leq 3), or Φ(3)−Φ(−2)\Phi(3) - \Phi(-2).